If \( f(x) = \frac{x+1}{x-1} \), then the value of \( f(f(x)) \) is equal to:
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Functions like \( f(x) = 1/x \) or \( f(x) = (x+1)/(x-1) \) are special because they are self-inverses. If you recognize this property, you can immediately identify that applying the function twice returns the original input \( x \).