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if f x frac 27 2x frac 1 ...
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If $f(x) = \frac{(27-2x)^{\frac{1}{3}} - 3}{9 - 3(243+5x)^{\frac{1}{5}}}, x \ne 0$ is continuous at $x = 0$, then the value of $f(0)$ is
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Use L'Hôpital's Rule for complex radical limits in $0/0$ form.
MHT CET - 2025
MHT CET
Updated On:
May 12, 2026
$\frac{2}{3}$
6
2
$\frac{1}{3}$
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The Correct Option is
C
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