Question:medium

If $f(x) = \frac{(27-2x)^{\frac{1}{3}} - 3}{9 - 3(243+5x)^{\frac{1}{5}}}, x \ne 0$ is continuous at $x = 0$, then the value of $f(0)$ is

Show Hint

Use L'Hôpital's Rule for complex radical limits in $0/0$ form.
Updated On: May 12, 2026
  • $\frac{2}{3}$
  • 6
  • 2
  • $\frac{1}{3}$
Show Solution

The Correct Option is C

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