Question:medium
If \[ f(x) = \begin{vmatrix} x & x^2 & x^3 \\ 1 & 2x & 3x^2 \\ 0 & 2 & 6x \end{vmatrix}, \] then \[ f'(x) \] is equal to:
If \[ f(x) = \begin{vmatrix} x & x^2 & x^3 \\ 1 & 2x & 3x^2 \\ 0 & 2 & 6x \end{vmatrix}, \] then \[ f'(x) \] is equal to:
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Always simplify the determinant first before differentiating — it saves time and avoids mistakes.
Updated On: May 1, 2026
- \( x^3 + 6x^2 \)
- \( 6x^3 \)
- \( 3x \)
- \( 6x^2 \)
- \( 0 \)
Show Solution
The Correct Option is B
Solution and Explanation
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