If $f(x) = \begin{cases} 3(1 - 2x^2), & 0<x<1 \\ 0, & \text{otherwise} \end{cases}$ is a probability density function of $X$, then $P\left(\frac{1}{4}<x<\frac{1}{3}\right)$ is
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Probability Tip: When dealing with Probability Density Functions, always double-check that your requested interval lies entirely within the domain where the function rule is defined. If it crosses boundaries, you must split the integral into pieces.