The function is $f(x) = 2x - \sin x$. To determine its monotonicity, we find the derivative: \[ f'(x) = \frac{d}{dx}(2x - \sin x) = 2 - \cos x \] Given that the range of $\cos x$ is $[-1, 1]$, it follows that $f'(x) = 2 - \cos x \geq 1$. As the derivative is consistently positive, the function $f(x)$ is always increasing.