If $f\left(\frac{x + 1}{2x - 1}\right) = 2x,\ x \in \mathbb{N}$, then the value of $f(2)$ is equal to:
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When solving functional equations of the type $f(g(x)) = h(x)$, you don't necessarily need to find the general formula for $f(x)$. Solving for a specific $x$ is usually much faster when only a single value like $f(2)$ is requested.