Question:medium

If \( [ ] \) denotes the greatest integer function, then \( \int_{1}^{2} [x^2] dx = \)

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For definite integrals involving \( [x^2] \), the critical points are always the square roots of integers. The result of such an integral can be visualized as the sum of areas of rectangles with heights equal to the integer values of the function.
Updated On: Jun 3, 2026
  • \( 5 + \sqrt{2} + \sqrt{3} \)
  • \( 5 + \sqrt{2} - \sqrt{3} \)
  • \( 5 - \sqrt{2} - \sqrt{3} \)
  • \( 5 - \sqrt{2} + \sqrt{3} \)
Show Solution

The Correct Option is C

Solution and Explanation

Step 1: Understanding the Concept:
The Greatest Integer Function, denoted by \([x]\), returns the largest integer less than or equal to \(x\).
The function \([x^2]\) is a step function. It changes its value only at points where the internal term \(x^2\) becomes an integer.
When integrating a step function over an interval \([a, b]\), we must split the integral into sub-intervals based on these "critical points" where the value jumps.
Within each sub-interval, the function remains constant, turning the integration into a series of area calculations for rectangles.
Step 2: Key Formula or Approach:
We identify the critical points for \(x^2\) in the interval \(x \in [1, 2]\).
As \(x\) goes from \(1\) to \(2\), \(x^2\) goes from \(1^2 = 1\) to \(2^2 = 4\).
The integer values that \(x^2\) takes in this range are \(1, 2, 3,\) and \(4\).
The critical values of \(x\) are therefore:
- \(x^2 = 1 \implies x = 1\)
- \(x^2 = 2 \implies x = \sqrt{2}\)
- \(x^2 = 3 \implies x = \sqrt{3}\)
- \(x^2 = 4 \implies x = 2\)
Step 3: Detailed Explanation:
We divide the integral into three parts based on these values:
\[ I = \int_{1}^{\sqrt{2}} [x^2] dx + \int_{\sqrt{2}}^{\sqrt{3}} [x^2] dx + \int_{\sqrt{3}}^{2} [x^2] dx \]
Now, let's determine the value of \([x^2]\) in each sub-interval:
1. For \(1 \leq x<\sqrt{2}\), we have \(1 \leq x^2<2\). Thus, \([x^2] = 1\).
2. For \(\sqrt{2} \leq x<\sqrt{3}\), we have \(2 \leq x^2<3\). Thus, \([x^2] = 2\).
3. For \(\sqrt{3} \leq x<2\), we have \(3 \leq x^2<4\). Thus, \([x^2] = 3\).
Now, we perform the simple constant integration:
\[ I = \int_{1}^{\sqrt{2}} 1 dx + \int_{\sqrt{2}}^{\sqrt{3}} 2 dx + \int_{\sqrt{3}}^{2} 3 dx \]
\[ I = [x]_{1}^{\sqrt{2}} + [2x]_{\sqrt{2}}^{\sqrt{3}} + [3x]_{\sqrt{3}}^{2} \]
Evaluating the bounds:
\[ I = (\sqrt{2} - 1) + (2\sqrt{3} - 2\sqrt{2}) + (3(2) - 3\sqrt{3}) \]
\[ I = \sqrt{2} - 1 + 2\sqrt{3} - 2\sqrt{2} + 6 - 3\sqrt{3} \]
Combining the constant and radical terms:
\[ I = (6 - 1) + (\sqrt{2} - 2\sqrt{2}) + (2\sqrt{3} - 3\sqrt{3}) \]
\[ I = 5 - \sqrt{2} - \sqrt{3} \]
Step 4: Final Answer:
The value of the definite integral is \(5 - \sqrt{2} - \sqrt{3}\).
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