Question:medium

If \(\cos \theta \csc \theta = -1\) and \(\theta\) lies in the second quadrant then \(\cos \theta =\)

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When you find a simple trigonometric ratio like \(\cot \theta = -1\), you can quickly visualize the angle. Cotangent is the ratio \(x/y\). For it to be -1, \(x = -y\). In the second quadrant, x is negative and y is positive, which fits. This corresponds to the line \(y = -x\) in the second quadrant, which makes a 45\(^{\circ}\) angle with the negative x-axis. The coordinates on the unit circle would be \((-\frac{1}{\sqrt{2}}, \frac{1}{\sqrt{2}})\), so \(\cos \theta\) is the x-coordinate, which is \(-\frac{1}{\sqrt{2}}\) or \(-\frac{\sqrt{2}}{2}\).
  • \(-\frac{\sqrt{3}}{2}\)
  • \(\frac{\sqrt{2}}{2}\)
  • \(-\frac{\sqrt{2}}{2}\)
  • \(-\sqrt{2}\)
Show Solution

The Correct Option is C

Solution and Explanation

Step 1: Understanding the Question:
We are given a trigonometric equation and the quadrant in which the angle θ lies. We need to find the specific value of cos θ.

Step 2: Key Formula or Approach (Alternate Method):
Rewrite cscθ as 1/sinθ to convert to cotθ, then solve for θ using reference angle and quadrant information.

Step 3: Detailed Explanation:
Given: cos θ · csc θ = -1, θ in QII. Replace csc θ = 1/sin θ: cos θ/sin θ = -1 → cot θ = -1. cot α = 1 gives reference angle α = 45° = π/4. In QII, θ = 180° - 45° = 135° = 3π/4. Now cos(135°) = -cos(45°) = -1/√2 = -√2/2.

Step 4: Final Answer:
The value of cos θ is -√2/2.
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