Question:medium

If \(\cos\left(2\sin^{-1}\alpha\right) = \frac{47}{72}\), where \(0 < \alpha < 1\), then the value of \(\alpha\) is

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\(\cos(2\sin^{-1} x) = 1 - 2x^2\).
Updated On: Apr 25, 2026
  • \(\frac{5}{12}\)
  • \(\frac{7}{12}\)
  • \(\frac{12}{13}\)
  • \(\frac{5}{13}\)
  • \(\frac{7}{13}\)
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The Correct Option is A

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