Question:medium

If COMPATIBLE is to CURIE, then AUDIENCE is to _____ ?

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Assign A=1, E=2, I=3, O=4, U=5, add up only the vowel values in each word, and match the totals.
Updated On: Jul 15, 2026
  • FREQUENT
  • OCEANIC
  • UNDERGONE
  • UNSEEN
Show Solution

The Correct Option is C

Solution and Explanation

Forget the words as whole units for a moment. This puzzle only cares about one thing: the vowels sitting inside each word, and a fixed number stamped on each vowel. Set the table first: $A=1$, $E=2$, $I=3$, $O=4$, $U=5$. Consonants are silent, they carry no weight at all, and the position of a vowel in the word does not matter either, only its identity and how many times it shows up.

Build a small table for the given pair before touching the answer choices:

  • COMPATIBLE: vowels are O, A, I, E, giving $4+1+3+2=10$.
  • CURIE: vowels are U, I, E, giving $5+3+2=10$.

The two scores tie at 10. That single fact is the whole rule of the game here, a word is "coded" into its partner when their vowel scores are equal. With the rule confirmed, apply it fresh to the second pair.

AUDIENCE breaks down into the vowels A, U, I, E, E:

\[ 1+5+3+2+2=13 \]

So whatever option is correct, its vowels have to add up to exactly 13. Run each option through the same table:

  1. FREQUENT: vowels E, U, E score $2+5+2=9$. Nine is short of thirteen, so this word is out.
  2. OCEANIC: vowels O, E, A, I score $4+2+1+3=10$. Ten is also short of thirteen, so this word is out too.
  3. UNDERGONE: vowels U, E, O, E score $5+2+4+2=13$. Thirteen lines up perfectly with AUDIENCE, so this word stays in the running.
  4. UNSEEN: vowels U, E, E score $5+2+2=9$. Nine again, so this word is out.

Only one option survives the check, UNDERGONE, and it survives by hitting the target sum exactly, not approximately. Since the coding rule is an equality test and not a "closest match" test, there is no ambiguity once one option ties the score perfectly.

Let's summarize:

  • Assign A=1, E=2, I=3, O=4, U=5 and ignore consonants completely.
  • Two words are linked when the sum of their vowel values is equal.
  • AUDIENCE sums to 13, and only UNDERGONE among the four options also sums to 13.

The word that AUDIENCE codes into is UNDERGONE.

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