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If an infinite slope of clay at a depth $5$ m has cohesion of $1$ t/m$^2$ and unit weight of $2$ t/m$^3$, then the stability number will be

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For slope stability problems, \[ \boxed{ N_s=\frac{c}{\gamma H} } \] Higher cohesion gives a larger stability number and hence a more stable slope.

Updated On: Jul 23, 2026

$0.1$
$0.2$
$0.3$
$0.4$

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The Correct Option is A

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If an infinite slope of clay at a depth \(5\) m has cohesion of \(1\) t/m\(^2\) and unit weight of \(2\) t/m\(^3\), then the stability number will be

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The Correct Option is A

Solution and Explanation

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