Question

If an electron in hydrogen atom jumps from \(3^{\text{rd}}\) orbit to \(2^{\text{nd}}\) orbit it emits a photon of wavelength '\(\lambda\)'. When it emits a photon from \(4^{\text{th}}\) orbit to \(3^{\text{rd}}\) orbit then the corresponding wavelength of emitted photon will be

• A. \(\frac{16}{25}\lambda\)
• B. \(\frac{9}{16}\lambda\)
• C. \(\frac{20}{7}\lambda\)
• D. \(\frac{20}{13}\lambda\)

Hint:

Shortcut: Compare inverse wavelengths using energy differences

Answer 1

The Correct Option is C