Step 1: Read off the sum and product. For $x^2-5x+6=0$, the sum of roots is the negative of the middle term and the product is the last term. \[ \alpha+\beta = 5, \qquad \alpha\beta = 6 \]
Step 2: Use a handy identity. We can write the sum of squares using the sum and product. \[ \alpha^2+\beta^2 = (\alpha+\beta)^2 - 2\alpha\beta \]
Step 3: Put in the numbers. \[ = 5^2 - 2 \times 6 = 25 - 12 = 13 \] \[ \boxed{13} \]