Question

If \( \alpha \) and \( \beta \) are the roots of the equation \( x^2 + 3x - 4 = 0 \), then \( \frac{1}{\alpha} + \frac{1}{\beta} \) is equal to:

• A. \( \frac{-3}{4} \)
• B. \( \frac{3}{4} \)
• C. \( \frac{-4}{3} \)
• D. \( \frac{4}{3} \)
• E. \( \frac{3}{2} \)

Hint:

For a quadratic equation \(ax^2 + bx + c = 0\), the sum of reciprocals of roots is: \[ \frac{1}{\alpha} + \frac{1}{\beta} = \frac{\alpha + \beta}{\alpha\beta} = -\frac{b}{c} \] provided \( \alpha, \beta \neq 0 \).

Answer 1

The Correct Option is B