Question

If A1B3C5D7E9 is coded as B2C4D6E8F0, how is M3N5O7P9 coded in the same way?

• A. N4O6P8Q0
• B. N4O6P8Q1
• C. L4M6N8O0
• D. N4O6P8R0
• E. O5P7Q9R0

Answer 1

The Correct Option is A

Step 1: Understanding the Question:
This is an alphanumeric coding problem. Both the letters and numbers are transformed.
Step 2: Detailed Explanation:

Cracking the code A1B3C5D7E9:
- Letters: A$\rightarrow$B, B$\rightarrow$C, C$\rightarrow$D, D$\rightarrow$E, E$\rightarrow$F. (All letters shifted by +1)
- Numbers: 1$\rightarrow$2, 3$\rightarrow$4, 5$\rightarrow$6, 7$\rightarrow$8, 9$\rightarrow$0. (All numbers incremented by +1, with 9 wrapping around to 0)

Applying logic to M3N5O7P9:
- M (letter) + 1 = N
- 3 (number) + 1 = 4
- N (letter) + 1 = O
- 5 (number) + 1 = 6
- O (letter) + 1 = P
- 7 (number) + 1 = 8
- P (letter) + 1 = Q
- 9 (number) + 1 = 10 $\rightarrow$ use only unit digit 0

Step 3: Final Answer:
The resulting code is "N4O6P8Q0", which corresponds to option (A).