Step 1: Component form:
The unit vector is $\left(\frac1{\sqrt2},\ \frac12,\ \cos\theta\right)$ with magnitude 1.
Step 2: Square and add:
$\frac12+\frac14+\cos^2\theta=1$, so $\cos^2\theta=\frac14$.
Step 3: Angles:
$\cos\theta=\frac12$ gives $\frac\pi3$ and $\cos\theta=-\frac12$ gives $\frac{2\pi}3$. Option (A).
Final Answer:
cos^2 theta = 1/4.
\[ \boxed{A} \]