If
\[
A(\operatorname{adj}A)=
\begin{bmatrix}
2026 & 0 & 0\\
0 & 2026 & 0\\
0 & 0 & 2026
\end{bmatrix},
\]
then the value of
\[
\left|\operatorname{adj}A\right|
\]
is equal to
\[
\_\_\_\_.
\]
Show Hint
For any scalar matrix \( A(\text{adj } A) = kI_n \), the determinant value is \( |A| = k \), and the determinant of its adjoint is always \( k^{n-1} \). Here, \( n=3 \), so the answer is immediately \( k^2 \).