If a share of ₹100 on which ₹70 has been paid is forfeited, then at which minimum price can it be re-issued?

Question

Let \(y=y(x)\) be the solution of the differential equation \[ x\frac{dy}{dx}=y-x^2\cot x,\quad x\in(0,\pi) \] If \(y\!\left(\frac{\pi}{2}\right)=\frac{\pi^2}{2}\), then \[ 6y\!\left(\frac{\pi}{6}\right)-8y\!\left(\frac{\pi}{4}\right) \] is equal to:

Answer 1

The minimum re-issue price for a forfeited share is the outstanding balance at the point of forfeiture. This outstanding amount is calculated as: \[ ₹100 - ₹70 = ₹30. \] Therefore, the minimum re-issue price stands at ₹30.

If a share of ₹100 on which ₹70 has been paid is forfeited, then at which minimum price can it be re-issued?

Show Hint

The Correct Option is B

Solution and Explanation

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