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If a random variable \( X \), defined such that \( E(X-1)^2 = 10 \) and \( E(X-2)^2 = 6 \) then mean \( (\mu) \) and variance \( (\sigma^2) \) are

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Always use the linearity of expectation first to clear out polynomial brackets. Treating \( E(X) \) and \( E(X^2) \) as simple standalone algebraic variables like \( u \) and \( v \) makes solving these systems quick and straightforward.

Updated On: Jul 9, 2026

\( \frac{2}{7}, \frac{4}{15} \)
\( \frac{2}{7}, \frac{15}{4} \)
\( \frac{7}{2}, \frac{4}{15} \)
\( \frac{7}{2}, \frac{15}{4} \)

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The Correct Option is D

Solution and Explanation

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If a random variable \( X \), defined such that \( E(X-1)^2 = 10 \) and \( E(X-2)^2 = 6 \) then mean \( (\mu) \) and variance \( (\sigma^2) \) are

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The Correct Option is D

Solution and Explanation

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