Question:medium

If a polygon has 54 diagonals, find the number of sides of the polygon.

Show Hint

Use the formula \(D = \frac{n(n-3)}{2}\) directly and quickly verify by substituting the value of \(n\) to avoid solving full quadratic in exam conditions.
Updated On: Jun 29, 2026
  • (A) 10
  • (B) 11
  • (C) 12
  • (D) 15
Show Solution

The Correct Option is C

Solution and Explanation

Step 1 : Understanding the Question:
In this problem, we are tasked with determining the specific number of sides of a convex polygon based on the information that it contains 54 diagonals. Geometrically, a diagonal is a line segment that connects two vertices that are not adjacent to each other. The challenge lies in establishing a mathematical relationship between the vertices, which correspond to the sides in a closed polygon, and the segments that can be drawn between them. This problem falls under the category of elementary geometry and combinatorics.
Step 2 : Key Formulas and approach:
The derivation of the diagonal formula is rooted in combination theory. If a polygon has $n$ vertices, the total number of line segments that can be formed by joining any two vertices is given by the combination formula ${}^nC_2$, which is mathematically expressed as $n(n-1)/2$. Out of these total segments, $n$ segments represent the actual boundary sides of the polygon. Therefore, to isolate the count of diagonals, we subtract the number of sides from the total segments. The resulting formula is:
\[ D = \frac{n(n - 1)}{2} - n = \frac{n^2 - n - 2n}{2} = \frac{n(n - 3)}{2} \]
Our approach will be to substitute $D = 54$ into this formula and solve for the unknown variable $n$.
Step 3 : Detailed Explanation:

We start by setting up the equation based on the given data: $54 = \frac{n(n - 3)}{2}$.

To clear the fraction and simplify the algebraic expression, we multiply both sides of the equation by 2, yielding $108 = n(n - 3)$.

Next, we expand the right side of the equation to form a standard quadratic expression: $n^2 - 3n = 108$.

By moving all terms to one side, we obtain the quadratic equation in its standard form: $n^2 - 3n - 108 = 0$.

To solve this, we employ the splitting the middle term (factorization) method. We need two integers whose product is $-108$ and whose algebraic sum is $-3$. The integers $-12$ and $+9$ satisfy these conditions perfectly.

We rewrite the equation as $n^2 - 12n + 9n - 108 = 0$ and group the terms: $n(n - 12) + 9(n - 12) = 0$.

Factoring out the common binomial gives $(n - 12)(n + 9) = 0$.

This equation provides two potential solutions: $n = 12$ and $n = -9$.

In the physical context of geometry, the number of sides of a polygon must be a positive integer greater than or equal to 3. Therefore, we discard $n = -9$.

Step 4 : Final Answer:
The value of $n$ is 12, indicating that the polygon has 12 sides.
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