If a man and a woman are heterozygous for a gene, and if they have three children, what is the chance that all three will also be heterozygous
Show Hint
Always use the product rule for independent "and" events, and the sum rule for mutually exclusive "or" events.
Here, the birth of each child is independent, so we multiply: \( (1/2)^3 = 1/8 \).