Question:medium

If $A$ is a square matrix of order $n$ such that $|\text{adj}(\text{adj} A)|=|A|^{25}$, then $n$ is equal to

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Logic Tip: Memorize the adjoint determinant hierarchy for a matrix $A$ of order $n$: 1. $|\text{adj} A| = |A|^{n-1}$ 2. $|\text{adj}(\text{adj} A)| = |A|^{(n-1)^2}$ 3. $\text{adj}(\text{adj} A) = |A|^{n-2} A$
Updated On: Apr 27, 2026
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The Correct Option is A

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