Question:easy

If \(A\) is a non-singular matrix and \(A^2-A+I = 0\), then \(A^{-1} = \ldots\)

Show Hint

Multiply the given relation by \(A^{-1}\).
Updated On: Oct 1, 2026
  • \(A\)
  • \(A-I\)
  • \(I-A\)
  • \(A+I\)
Show Solution

The Correct Option is C

Solution and Explanation

Step 1: Factor
$A^2-A+I=0$ gives $A(A-I)=-I$, so $A(I-A)=I$.

Step 2: Read the inverse
A matrix whose product with $A$ is $I$ is the inverse, so $A^{-1}=I-A$, option (C).

Final Answer:
$A^{-1}=I-A$, option (C). \[ \boxed{I-A} \]
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