Question

If a fair coin is tossed 8 times, then the probability of getting at most 2 heads is...

• A. \(\frac{37}{64}\)
• B. \(\frac{37}{256}\)
• C. \(\frac{37}{128}\)
• D. \(\frac{37}{512}\)

Hint:

Add the binomial probabilities for 0, 1 and 2 heads.

Answer 1

The Correct Option is B

Step 1: Count outcomes
There are $2^8 = 256$ equally likely outcomes. Outcomes with 0, 1 and 2 heads are $1, 8, 28$.

Step 2: Probability
$\frac{37}{256}$. Option (B).

Final Answer:
37/256. \[ \boxed{\text{(B)}\ \frac{37}{256}} \]