To solve this problem, we need to find the distance covered by the car. We are given the initial speed, final speed, and the time duration.
First, let's identify the values given in the problem:
Initial speed (u): 0 km/h (since the car is at rest)
Final speed (v): 144 km/h
Time (t): 20 seconds
Convert the final speed from km/h to m/s:
1 \text{ km/h} = \frac{1000}{3600} \text{ m/s}.
Therefore, v = 144 \times \frac{1000}{3600} = 40 \text{ m/s}.
Use the equation of motion: v = u + at to determine the acceleration (a).
Substituting the known values, we get:
40 = 0 + a \times 20.
Thus, a = \frac{40}{20} = 2 \text{ m/s}^2.
Now, use the formula for the distance covered under uniform acceleration:
s = ut + \frac{1}{2} a t^2.
Plugging in the known values:
s = 0 \times 20 + \frac{1}{2} \times 2 \times (20)^2.
Therefore, s = 0 + \frac{1}{2} \times 2 \times 400 = 400 \text{ m}.
Hence, the distance covered by the car is 400 meters. This matches the correct option.