Question:medium
If \( A = \begin{vmatrix} 8 & 27 & 125 \\ 2 & 3 & 5 \\ 1 & 1 & 1 \end{vmatrix} \), then the value of \( A^2 \) is equal to:
If \( A = \begin{vmatrix} 8 & 27 & 125 \\ 2 & 3 & 5 \\ 1 & 1 & 1 \end{vmatrix} \), then the value of \( A^2 \) is equal to:
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For determinants involving cubes or squares, row operations that target the '1s' in the bottom row usually yield the fastest path to the solution.
Updated On: May 2, 2026
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- $64$
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The Correct Option is
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