Question:medium
If \( A = \begin{pmatrix} 1 & 1 \\ 1 & 1 \end{pmatrix} \), then the value of \( A^{2017} \) is equal to:
If \( A = \begin{pmatrix} 1 & 1 \\ 1 & 1 \end{pmatrix} \), then the value of \( A^{2017} \) is equal to:
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For any matrix \( A \) where all elements are \( 1 \) and the order is \( n \), the identity \( A^k = n^{k-1}A \) holds true. This is a very frequent pattern in linear algebra assessments.
Updated On: May 1, 2026
- \( 2^{2015} A \)
- \( 2^{2016} A \)
- \( 2^{2014} A \)
- \( 2^{2017} A \)
- \( 2^{2020} A \)
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The Correct Option is B
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