Question:medium
If \( A = \begin{bmatrix} x & 1 & -x \\ 0 & 1 & -1 \\ x & 0 & 7 \end{bmatrix} \) and \( \det(A) = \begin{vmatrix} 3 & 0 & 1 \\ 2 & -1 & 2 \\ 0 & 0 & 3 \end{vmatrix} \), then the value of \( x \) is:
If \( A = \begin{bmatrix} x & 1 & -x \\ 0 & 1 & -1 \\ x & 0 & 7 \end{bmatrix} \) and \( \det(A) = \begin{vmatrix} 3 & 0 & 1 \\ 2 & -1 & 2 \\ 0 & 0 & 3 \end{vmatrix} \), then the value of \( x \) is:
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When equating two determinants, solve the constant side first to determine the target value for the variable side.
Updated On: May 2, 2026
- $-3$
- $3$
- $2$
- $-8$
- $-2$
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The Correct Option is A
Solution and Explanation
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