Question:medium

If \[ A= \begin{bmatrix} \frac12 & \frac{\sqrt3}{2}\\ -\frac{\sqrt3}{2} & \frac12 \end{bmatrix}, \] then $A^{10}=$}

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Whenever a matrix contains $\cos\theta$ and $\sin\theta$ in rotation form, use \[ R(\theta)^n=R(n\theta). \] This avoids lengthy matrix multiplication.
Updated On: Jun 17, 2026
  • $-A$
  • $A$
  • $A^2$
  • $-A^2$
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The Correct Option is D

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