Question:medium
If \( A = \begin{bmatrix} 2 & 1 3 & 2 \end{bmatrix} \), then \( A^{-1} \) is
If \( A = \begin{bmatrix} 2 & 1 3 & 2 \end{bmatrix} \), then \( A^{-1} \) is
Show Hint
For \(2 \times 2\) matrices, always remember: swap diagonal, change signs of off-diagonal, then divide by determinant.
Updated On: May 1, 2026
- \( \begin{bmatrix}2 & -1 -3 & 2 \end{bmatrix} \)
- \( \begin{bmatrix}2 & 1 3 & 2 \end{bmatrix} \)
- \( \begin{bmatrix}2 & -1 3 & -2 \end{bmatrix} \)
- \( \begin{bmatrix}-2 & 1 3 & -2 \end{bmatrix} \)
- \( \begin{bmatrix}1 & 0 0 & 1 \end{bmatrix} \)
Show Solution
The Correct Option is A
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