Question:medium
If \( A = \begin{bmatrix} 0 & -1 & 0 \\ 1 & 0 & 0 \\ 0 & 0 & -1 \end{bmatrix} \), then \( A^{-1} \) is:
If \( A = \begin{bmatrix} 0 & -1 & 0 \\ 1 & 0 & 0 \\ 0 & 0 & -1 \end{bmatrix} \), then \( A^{-1} \) is:
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For matrices with only \( 0, 1, \text{ or } -1 \), check for orthogonality first. If each row and each column has exactly one non-zero entry, and that entry's square is 1, the inverse is always the transpose.
Updated On: May 1, 2026
- \( A^T \)
- \( A^2 \)
- \( A \)
- \( I \)
- \( 0 \)
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The Correct Option is A
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