Question:medium

If \(A,B,C\) are the vertices of a triangle \(ABC\), \[ AB=2,\qquad BC=3,\qquad CA=4, \] then \[ \overrightarrow{AB}\cdot\overrightarrow{BC} + \overrightarrow{BC}\cdot\overrightarrow{CA} + \overrightarrow{CA}\cdot\overrightarrow{AB} = \]

Show Hint

Whenever you see \[ \overrightarrow{AB}\cdot\overrightarrow{BC} + \overrightarrow{BC}\cdot\overrightarrow{CA} + \overrightarrow{CA}\cdot\overrightarrow{AB}, \] use \[ \overrightarrow{AB} +\overrightarrow{BC} +\overrightarrow{CA} =0 \] and square both sides.
Updated On: Jun 17, 2026
  • \(9\)
  • \(-\dfrac{29}{2}\)
  • \(-\dfrac{25}{2}\)
  • \(29\)
Show Solution

The Correct Option is B

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