Question:medium

If \(A+B=C\) and \(A^2+B^2=C^2\), then the angle between vectors \(A\) and \(B\) is

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Use \(C^2=A^2+B^2+2AB\cos\theta\). If \(C^2=A^2+B^2\), then \(\cos\theta=0\), so \(\theta=90^\circ\).
Updated On: May 7, 2026
  • \(0^\circ\)
  • \(60^\circ\)
  • \(90^\circ\)
  • \(120^\circ\)
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The Correct Option is C

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