Question:medium

If A and B are positive acute angles satisfying 3cos²A+2cos²B=4 and (3sin A)/(sin B)=(2cos B)/(cos A), then the value of A+2B is equal to:

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Convert products of sine and cosine into double-angle form.

Updated On: Mar 19, 2026

\(\dfrac{\pi}{6}\)
\(\dfrac{\pi}{2}\)
\(\dfrac{\pi}{3}\)
(π)/(4)

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The Correct Option is C

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