Question:medium

If \(a\) and \(b\) are non-zero roots of \(6x^2+ax+b=0\), then the least value of \(x^2+ax+b\) is

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Minimum of \(px^2+qx+r\) occurs at \(x=-\frac q{2p}\).

Updated On: Mar 23, 2026

\(\dfrac23\)
\(-\dfrac94\)
\(\dfrac94\)
\(1\)

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The Correct Option is B

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