Question:medium

If \(a\) and \(b\) are arbitrary constants, then the differential equation representing the family of curves \[ y=a\sin(x+b) \] is

Show Hint

For \(y=a\sin(x+b)\), differentiating twice gives the relation \(y''=-y\).
  • \(\frac{d^2y}{dx^2}-y=0\)
  • \(\frac{d^2y}{dx^2}+y=0\)
  • \(\frac{d^2y}{dx^2}-y^2=0\)
  • \(\frac{dy}{dx}-y=0\)
Show Solution

The Correct Option is B

Solution and Explanation

Was this answer helpful?
0