Question:medium

If a\(95\% \)confidence interval for the population mean was reported to be 160 to 170 and\(σ = 25\), then the size of the sample used in this study is:

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When calculating the sample size for a confidence interval, the margin of error formula \( E = Z \cdot \frac{\sigma}{\sqrt{n}} \) is very useful. The key step is isolating \( n \) after finding the margin of error. Be sure to square your result for \( \sqrt{n} \) to get the sample size. Also, remember to round the sample size to the nearest whole number since you cannot have a fraction of a sample.

Updated On: Jun 6, 2026
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The Correct Option is A

Solution and Explanation

The formula for the margin of error (E) in a confidence interval is given by \(E = Z \cdot \frac{\sigma}{\sqrt{n}}\).

In this formula, \(E\) represents half the width of the interval, \(Z\) is 1.96, and \(\sigma\) is 25.

The calculated width of the confidence interval is \(170 - 160 = 10\). Therefore, the margin of error is \(E = \frac{10}{2} = 5\).

Substituting these values into the margin of error formula yields \(5 = 1.96 \cdot \frac{25}{\sqrt{n}}\).

Solving for \(n\), we first find \(\sqrt{n} = \frac{1.96 \cdot 25}{5} = 9.8\).

Then, squaring both sides gives \(n = 9.8^2 = 96.04\).

Consequently, the required sample size is \(n = 96\).

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