Question:medium

If a 95% confidence interval for a population mean was reported to be 132 to 160 and sample standard deviation s = 50, then the size of the sample in the study is:
(Given \(Z_{0.025}\) = 1.96)

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The margin of error is the key link between the confidence interval, standard deviation, and sample size. If you are given the interval, you can always calculate the ME and then use its formula to solve for any unknown component.
Updated On: Mar 27, 2026
  • 90
  • 95
  • 50
  • 49
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The Correct Option is D

Solution and Explanation

Step 1: Conceptual Foundation:
A confidence interval delineates a range of probable values for a population parameter. The breadth of this interval is influenced by the chosen confidence level, the variability within the sample, and the sample's size. The formula for a confidence interval can be utilized to deduce the required sample size.
Step 2: Core Formula and Methodology:
The standard formula for a confidence interval for the mean is:\[ \text{CI} = \bar{x} \pm \text{Margin of Error (ME)} \]Where the Margin of Error is defined as:\[ \text{ME} = Z_{\alpha/2} \times \frac{s}{\sqrt{n}} \]The sample mean (\(\bar{x}\)) and the margin of error can be extracted directly from the provided interval.
Step 3: Detailed Calculation:
The provided 95% confidence interval is [132, 160].
1. Determination of Sample Mean (\(\bar{x}\)): The sample mean is the central point of the confidence interval.\[ \bar{x} = \frac{\text{Upper Limit} + \text{Lower Limit}}{2} = \frac{160 + 132}{2} = \frac{292}{2} = 146 \]2. Calculation of Margin of Error (ME): The margin of error represents half the width of the interval.\[ \text{ME} = \frac{\text{Upper Limit} - \text{Lower Limit}}{2} = \frac{160 - 132}{2} = \frac{28}{2} = 14 \]3. Application of ME Formula to Determine n:Given values:- ME = 14- Sample standard deviation, s = 50- For a 95% confidence level, the critical Z-value, \(Z_{0.025}\), is 1.96.Substituting these values into the formula:\[ 14 = 1.96 \times \frac{50}{\sqrt{n}} \]Reordering the equation to isolate \(\sqrt{n}\):\[ \sqrt{n} = \frac{1.96 \times 50}{14} \]\[ \sqrt{n} = \frac{98}{14} = 7 \]Squaring both sides to ascertain n:\[ n = 7^2 = 49 \]Step 4: Conclusive Result:
The sample size employed in the study is 49.
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