Question:medium
If $a_1, a_2, a_3, a_4$ are in A.P., then $\frac{1}{\sqrt{a_1} + \sqrt{a_2}} + \frac{1}{\sqrt{a_2} + \sqrt{a_3}} + \frac{1}{\sqrt{a_3} + \sqrt{a_4}} =$
If $a_1, a_2, a_3, a_4$ are in A.P., then $\frac{1}{\sqrt{a_1} + \sqrt{a_2}} + \frac{1}{\sqrt{a_2} + \sqrt{a_3}} + \frac{1}{\sqrt{a_3} + \sqrt{a_4}} =$
Show Hint
In any A.P., the sum of terms equidistant from the beginning and the end is always constant. This means \( a_1 + a_n = a_2 + a_{n-1} = a_3 + a_{n-2} \), etc. This property makes finding the total sum very quick if you have any of these pairs.
Updated On: May 2, 2026
- \( 90 \)
- \( 900 \)
- \( 350 \)
- \( 450 \)
- \( 730 \)
Show Solution
The Correct Option is D
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