Step 1: Direct counting via block sizes:
Since 1 and 2 must be equivalent, treat \(\{1,2\}\) as one merged unit; the remaining element 3 is either in this block or its own block.
Step 2: Case 1:
3 joins \(\{1,2\}\): gives the single block \(\{1,2,3\}\).
Step 3: Case 2:
3 stays alone: gives blocks \(\{1,2\},\{3\}\).
Final Answer:
Exactly \(\boxed{2}\) partitions arise, so 2 equivalence relations contain \((1,2)\).