Question:medium

If \(9^{\frac{1}{2}} - 2^{2x - 2} = 4^{x} - 3^{2x - 3}\), then \(x\) is:

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For exponential equations, try to express both sides with the same base or test the given optionss in the original equation, especially if the equation is complex.
Updated On: Jun 15, 2026
  • 3/4
  • 2/3
  • 4/9
  • 3/5
  • 3/2
Show Solution

The Correct Option is

Solution and Explanation

Step 1: Understanding the Concept:
Express all terms using base 3 and base 2 to group similar exponential terms.
Step 2: Key Formula or Approach:
\( a^m = a^n \Rightarrow m = n \). Rearrange bases to opposite sides.
Step 3: Detailed Explanation:
\( (3^2)^{x-1/2} - 2^{2x-2} = (2^2)^x - 3^{2x-3} \).
\( 3^{2x-1} - 2^{2x-2} = 2^{2x} - 3^{2x-3} \).
Rearranging:
\( 3^{2x-1} + 3^{2x-3} = 2^{2x} + 2^{2x-2} \).
Factor out the lowest powers:
\( 3^{2x-3}(3^2 + 1) = 2^{2x-2}(2^2 + 1) \).
\( 3^{2x-3}(10) = 2^{2x-2}(5) \).
\( 3^{2x-3} \cdot 2 = 2^{2x-2} \).
\( 3^{2x-3} = 2^{2x-2} / 2 = 2^{2x-3} \).
Since bases are different, the equality \( 3^A = 2^A \) only holds if \( A = 0 \).
\( 2x - 3 = 0 \Rightarrow x = 3/2 \).
Step 4: Final Answer:
The value of x is 3/2.
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