Question:medium

If $3A - B = \begin{bmatrix} 1 & 2 & -1\\ 0 & 1 & -2\\ -1 & 1 & 4 \end{bmatrix} $ and $A^{-1} = \begin{bmatrix} 1 & 2 & 1\\ 0 & 1 & -1\\ 0 & 0 & 1 \end{bmatrix}$, then $B = ?$

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Use inverse matrices to find $A$, then substitute into given equation.
Updated On: Apr 23, 2026
  • $\begin{bmatrix}2 & -8 & -8\\ 0 & 1 & -1\\ 0 & -1 & 1\end{bmatrix}$
  • $\begin{bmatrix}2 & -8 & -8\\ 0 & 2 & -1\\ 0 & -1 & 2\end{bmatrix}$
  • $\begin{bmatrix}2 & -8 & -8\\ 0 & 2 & 5\\ 1 & -1 & -1\end{bmatrix}$
  • $\begin{bmatrix}2 & -8 & -8\\ 0 & 1 & 5\\ 1 & -1 & 1\end{bmatrix}$
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The Correct Option is C

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