Question

If 300 J of heat energy is used to raise the temperature of one mole of an ideal gas by 10 K at constant pressure, then heat energy required to raise its temperature by 10 K at constant volume is $(R=8.3\text{ J mol}^{-1}\text{K}^{-1})$

• A. 117 J
• B. 150 J
• C. 183 J
• D. 217 J
• E. 300 J

Hint:

Logic Tip: You can calculate this even faster without finding $C_p$ explicitly. The difference in heat is simply the work done: $Q_p - Q_v = nR\Delta T$. Therefore, $Q_v = Q_p - nR\Delta T = 300 - (1)(8.3)(10) = 300 - 83 = 217$ J.

Answer 1

The Correct Option is D