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If \(2\sin^{-1}x=\sin^{-1}k\), then \(k=\)

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For inverse trigonometric questions, assume \(\sin^{-1}x=\theta\), then convert the expression into normal trigonometric form.

Updated On: May 7, 2026

\(2x\sqrt{1-x^2}\)
\(2x\)
\(x^2\)
\(1-2x^2\)

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The Correct Option is A

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