Question:medium

If \( 15^{\text{th}} \) August, 2023 was on Tuesday, then on which day of the week would the Independence Day be celebrated in the year 2040?

Show Hint

For the same date in different years, use the shortcut: \[ \text{Odd Days} = (\text{Year Difference} + \text{Number of Leap Years}) \pmod 7 \] Then move forward that many days from the given weekday.
  • Tuesday
  • Wednesday
  • Thursday
  • Friday
Show Solution

The Correct Option is B

Solution and Explanation


Step 1:
\textbf Calculate the number of years between the two dates. \[ 2040 - 2023 = 17 \text{ years} \] Thus, the period from \(15^{\text{th}}\) August 2023 to \(15^{\text{th}}\) August 2040 spans \(17\) years.

Step 2:
\textbf Count the leap years in this interval. The leap years occurring before \(15^{\text{th}}\) August 2040 are: \[ 2024,\; 2028,\; 2032,\; 2036,\; 2040 \] Hence, \[ \text{Number of leap years} = 5 \]

Step 3:
\textbf Calculate the total odd days. Every year contributes one odd day, and each leap year contributes one additional odd day. \[ \text{Total Odd Days} = 17 + 5 = 22 \] Now, \[ 22 \mod 7 = 1 \] Therefore, there is a net advancement of \(1\) day.

Step 4:
\textbf Determine the required day. Given: \[ 15^{\text{th}} \text{ August, 2023} = \text{Tuesday} \] Adding \(1\) day: \[ \text{Tuesday} + 1 = \text{Wednesday} \] Hence, Independence Day in the year \(2040\) will be celebrated on Wednesday.
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