Question:medium

If 100 fewer students had applied and 50 fewer were selected, the ratio selected:unselected would be \(7:4\). In reality, the ratio selected:unselected was \(3:2\). How many students had applied?

Show Hint

Translate ratio statements into variables first (\(3k,2k\)). For “if less/more” scenarios, adjust both selected and unselected consistently before forming the new ratio.
Updated On: Jan 13, 2026
  • 325
  • 415
  • 375
  • 425
Show Solution

The Correct Option is C

Solution and Explanation

Step 1: Initial Ratio
Assume the ratio of selected to unselected is \(3:2\).
Let selected \(=3k\), unselected \(=2k\), and total applicants \(A=5k\).
Step 2: Hypothetical Change
If \(100\) applicants are removed, the new values are: applied \(A-100\), selected \(3k-50\), and unselected \((A-100)-(3k-50)=(2k-50)\).
The new ratio is \((3k-50):(2k-50)=7:4\).
Step 3: Solve for \(k\)
\(\displaystyle \frac{3k-50}{2k-50}=\frac{7}{4}⇒ 4(3k-50)=7(2k-50)⇒ 12k-200=14k-350⇒ 2k=150⇒ k=75.\)
Therefore, \(A=5k=375\).
\[\boxed{375}\]
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