If \( 0^\circ < A < 90^\circ \), then simplify \( \sqrt{\frac{1+\sin A}{1-\sin A}} \)
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If you see \( \sqrt{\frac{1+\sin A}{1-\sin A}} \), immediately try converting denominator using \(1-\sin^2 A = \cos^2 A\). This is a standard JEE/board-level identity pattern.