Question

Identity Z in the sequence of reactions, $CH_3 CH_2 CH=CH_2 \xrightarrow{HBr/H_2 O_2}Y \xrightarrow{C_2H_5 ON_a}Z$

• A. $CH_3-(CH_2)_3-O-CH_2CH_3$
• B. $(CH_3)_2 CH_2-O-CH_2CH_3$
• C. $ CH_3(CH_2)_4-OCH_3$
• D. $ CH_3 CH_2CH(CH_3)OCH_2CH_3$

Answer 1

The Correct Option is A

To identify the compound Z in the given sequence of reactions, let's analyze each step in detail.

1. Reaction 1: CH_3CH_2CH=CH_2 \xrightarrow{HBr/H_2O_2} Y
   • This reaction involves the anti-Markovnikov addition of HBr to an alkene in the presence of hydrogen peroxide (H₂O₂). The peroxide effect causes the Br^- ion to add to the less substituted carbon of the double bond.
   • Starting compound: CH_3CH_2CH=CH_2 (1-butene)
   • Product Y after anti-Markovnikov addition: CH_3CH_2CH_2CH_2Br (1-bromobutane)
2. Reaction 2: CH_3CH_2CH_2CH_2Br \xrightarrow{C_2H_5ONa} Z
   • This step involves the reaction of 1-bromobutane with sodium ethoxide (C₂H₅ONa), which is a strong base, leading to a nucleophilic substitution reaction to form an ether.
   • The reaction will involve a substitution where the bromine atom is replaced by an ethoxy group (OCH₂CH₃).
   • The final product Z is: CH_3(CH_2)_3OCH_2CH_3 (butyl ethyl ether)

Based on these steps, the correct identity of compound Z is CH_3-(CH_2)_3-O-CH_2CH_3 (butyl ethyl ether), matching the correct answer provided in the options.