Question

Identify the total number of complexes from following list having monodentate ligands in them
(a) Tetracyanonickelate (II) ion
(b) Potassium hexafluoroaluminate (III)
(c) Tetraamminecopper(II) ion
(d) Potassium trioxalatoaluminate (III)

• A. \(4\)
• B. \(3\)
• C. \(2\)
• D. \(1\)

Hint:

Cyanide, fluoride and ammine are monodentate; oxalate is bidentate.

Answer 1

The Correct Option is B

Step 1: Classify each ligand
cyano = one donor C; fluoro = one donor F; ammine = one donor N; oxalato = two donor O atoms.

Step 2: Count
Monodentate in a, b and c, so the count is 3, option (B).

Final Answer:
The count is 3, option (B). \[ \boxed{3} \]