Step 1: Recall what reductive ozonolysis does.
It cleaves a C=C double bond and turns each end into a C=O group, so working backwards from the carbonyl product reveals exactly where that double bond used to sit.
Step 2: Look at the given product.
It's 5-oxohexanal, $\text{CH}_3-\text{CO}-\text{CH}_2-\text{CH}_2-\text{CH}_2-\text{CHO}$, a six carbon chain with a ketone at one end and an aldehyde at the other.
Step 3: Rebuild the ring.
Join the ketone carbon back to the aldehyde carbon with a double bond, closing a five-membered ring and leaving a methyl group on the carbon that used to carry the ketone.
Step 4: Name the reconstructed alkene.
That structure is a methylcyclopentene with the double bond and methyl positioned as described in the matching option.
Final answer: Option 3.